Section 1.1.5 of SICP introduces the concept of normal order evaluation. Lisp traditionally evaluates all the arguments before applying functions, but with normal order evaluation this is reversed. The functions are expanded out as far as possible before any of the arguments are evaluated. It’s the Evil Universe version of Lisp!!

Now, when I’m confronted with problems having to do with normal order evaluation… for some reason my mind switches off. All of my Lisp experience is with the standard applicative order evaluation… and that’s the way I think. I have a really hard time imagining how normal order evaluation would break things out differently.

(And that’s the thing about SICP. It’s written for guys that scored higher on the SAT than I did… guys that actually paid attention in math class and did their homework. And it’s a tough book even for *them*— and they have the benefit of peers and TA’s and professors. And just because you can skirt by problems like Exercise 1.5, it doesn’t mean you’re through. This stuff will come back to haunt you in 1.20 and probably even more!)

So there I am having a pity party for myself: I’m a dummy. I have intellectual limits and weaknesses. Google doesn’t return much useful stuff on this topic. I don’t have a com-sci degree. I missed my chance to go to MIT and be somebody…. And then the light bulb goes off: Common Lisp pretty much comes with a normal order evaluator built in. They’re called macros! I can use Common Lisp as a sort of substitute professor to help me practice with normal order evaluation– and Common Lisp will even help me by checking the expansions that I’ve done by hand!

So I rewrite the Scheme example from SICP into Common Lisp macros:

CL-USER> (defmacro square (x)

`(* ,x ,x))

**SQUARE**

CL-USER> (defmacro sum-of-squares (x y)

`(+ (square ,x) (square ,y)))

**SUM-OF-SQUARES**

CL-USER> (defmacro f (a)

`(sum-of-squares (+ ,a 1) (* ,a 2)))

**F**

CL-USER> (macroexpand ‘(f 5))

**(+ (SQUARE (+ 5 1)) (SQUARE (* 5 2)))**

**T**

Oops. We’re close here, but we’re still not getting the same expansion as the book. For some reason we’re not expanding out the SQUARE macro. It must be because the reader waits until we have a macro name an the far left side before it expands one. Maybe we can make it work by using a series of macroexpand-1 commands:

CL-USER> (macroexpand-1 ‘(f 5))

(SUM-OF-SQUARES (+ 5 1) (* 5 2))

**T**

CL-USER> (macroexpand-1 ‘(SUM-OF-SQUARES (+ 5 1) (* 5 2)))

**(+ (SQUARE (+ 5 1)) (SQUARE (* 5 2)))**

**T**

CL-USER> (macroexpand-1 ‘(+ (SQUARE (+ 5 1)) (SQUARE (* 5 2))))

**(+ (SQUARE (+ 5 1)) (SQUARE (* 5 2)))**

**NIL**

CL-USER> (macroexpand-1 ‘(SQUARE (+ 5 1)))

**(* (+ 5 1) (+ 5 1))
T**

CL-USER> (macroexpand-1 ‘(SQUARE (* 5 2)))

**(* (* 5 2) (* 5 2))**

T

T

CL-USER> (+ (* (+ 5 1) (+ 5 1)) (* (* 5 2) (* 5 2)))

**136**

Okay, we can force it work… and then cut and paste the results together to get the same expansion that the text comes up with. But I hate cutting and pasting in Emacs. Let’s rewrite the sum-of-squares macro so that it does all of that work for me:

CL-USER> (defmacro sum-of-squares (x y)

(list ‘+

(macroexpand-1 `(square ,x))

(macroexpand-1 `(square ,y))))

**SUM-OF-SQUARES**

CL-USER> (macroexpand ‘(f 5))

**(+ (* (+ 5 1) (+ 5 1)) (* (* 5 2) (* 5 2)))
T**

There’s probably a more elegant way to pull that off, but we get the job done. So now we not only have a little practice with macros and normal order evaluation, but we have techniques at our disposal that allow us to switch back and forth from normal order to applicative order evaluation whenever we choose. In what other language can you do that?!

(To see these techniques applied to SICP exercises 1.5 and 1.20, please see my study notes in this text file.)

August 21, 2007 at 2:26 pm |

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